SOLUTION: An urn contains 8 balls identical in every aspect except color. There is 1 red ball, 2 green balls, and 5 blue balls. You draw two balls from the urn, but replace the first ball be

Question 582685: An urn contains 8 balls identical in every aspect except color. There is 1 red ball, 2 green balls, and 5 blue balls. You draw two balls from the urn, but replace the first ball before drawing the second. Find the probability that the first ball is blue and the second is green.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
An urn contains 8 balls identical in every aspect except color. There is 1 red ball, 2 green balls, and 5 blue balls. You draw two balls from the urn, but replace the first ball before drawing the second. Find the probability that the first ball is blue and the second is green.
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"With replacement" makes the events independent.
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P(blue and green) = P(blue)*P(green) = (5/8)(2/8) = 10/64
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Cheers,
Stan H.
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