SOLUTION: how many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill 4 positions?

Question 581303: how many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill 4 positions?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many ways can two republicans, one democrat, and one independent be chosen from nine republicans, five democrats, and two independents to fill 4 positions?
--------
Ans: 9C2*5C1*4C1 = 36*5*4 = 720
=============
Cheers,
Stan H.
==============

RELATED QUESTIONS
There are six Republican, five Democrat, and four independent candidates. How many... (answered by ikleyn)

decide if the situation involves permutations, or combinations. explain the reasoning. (answered by ikleyn)

in how many ways can a subcommittee of four be chosen from a Senate committee of five... (answered by Boreal)

In how many ways can a subcommittee of five be chosen from a Senate committee of six... (answered by ewatrrr)

a committee of five congressmen will be selected from a group of four democrats and six... (answered by ikleyn)

How many subcommittees each consisting of 2 Republicans and 1 Democrat, can be formed... (answered by Ratman99)

How many subcommittees, each consisting of 2 Republicans and 1 Democrat, can be formed... (answered by stanbon)

How many subcommittees, each consisting of 2 Republicans and 1 Democrat, can be formed... (answered by edjones)

a commitee consists of 10 republicans and 8 democrats. in how many ways can a subcommitee (answered by stanbon)