SOLUTION: Consider a binomial random variable where the number of trials is 9 and the probability of success on each trial is 0.43. Find the mean and standard deviation of this random vari

SOLUTION: Consider a binomial random variable where the number of trials is 9 and the probability of success on each trial is 0.43. Find the mean and standard deviation of this random vari

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Question 576566: Consider a binomial random variable where the number of trials is 9 and the probability of success on each trial is 0.43. Find the mean and standard deviation of this random variable.
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
mean = np = 9*0.43 = 3.87

standard deviation = sqrt(np(1-p)) = sqrt(9*0.43*(1-0.43)) = 1.485227
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