SOLUTION: Suppose a survey of 1,000 citizens finds that the proportion of respondents who report not having health insurance is .200. Would this sample result be unusual if the true proporti

Question 573830: Suppose a survey of 1,000 citizens finds that the proportion of respondents who report not having health insurance is .200. Would this sample result be unusual if the true proportion in the population is .158?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose a survey of 1,000 citizens finds that the proportion of respondents who report not having health insurance is .200. Would this sample result be unusual if the true proportion in the population is .158?
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z(0.2) = (0.2-0.158)/sqrt[0.158*0.842/1000] = 3.6414
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Yes, 0.2 is unuaual. It is over 3 standard deviations above the mean.
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cheers,
Stan H.
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