SOLUTION: 6 defects are observed in 283 unites produced, I need to determine the probability of obtaining units with zero defects (yield) 6/283=.021201 .021201 this is where i am

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Question 565123: 6 defects are observed in 283 unites produced, I need to determine the probability of obtaining units with zero defects (yield)

6/283=.021201
.021201
this is where i am stuck. is this binomial ?
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
6 defects are observed in 283 unites produced, I need to determine the probability of obtaining units with zero defects (yield)
6/283=.021201
.021201
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It's binomial because each unit is either defective or not defective.
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6/283 is the probability of a unit being defective.
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1 - (6/283) is the probability of a unit not being defective.
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1 - (6/283) = 1 - 0.021201 = 0.9788
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Cheers,
Stan H.
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