# SOLUTION: Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games.

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games.       Log On

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 Click here to see ALL problems on Probability-and-statistics Question 560798: Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games. What is the probability that he will win 3 and lose only one?Answer by stanbon(57982)   (Show Source): You can put this solution on YOUR website!Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games. What is the probability that he will win 3 and lose only one? --------------------- Binomial Problem with n = 4 and p(lose) = 2/3 --- P(x = 1) = 4C1*(2/3)*(1/3)^3 = 0.0988 =========== Cheers, Stan H. =============