SOLUTION: Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games.

Question 560798: Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games. What is the probability that he will win 3 and lose only one?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Arthur normally wins 1 out of every 3 backgammon games he plays. In other words, the probability that Arthur wins when he plays backgammon is 1/3. Suppose Arthur plays 4 games. What is the probability that he will win 3 and lose only one?
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Binomial Problem with n = 4 and p(lose) = 2/3
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P(x = 1) = 4C1*(2/3)*(1/3)^3 = 0.0988
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Cheers,
Stan H.
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