SOLUTION: Given a normal distribution μ = 100 with and σ=10, if you select a sample of n=25 what is the probability that X is a. less than 95 c. above 102.2?

Question 554128: Given a normal distribution μ = 100 with and σ=10, if you select a sample of n=25 what is the probability that X is
a. less than 95
c. above 102.2?
Found 2 solutions by stanbon, kkasko:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Given a normal distribution μ = 100 with and σ=10, if you select a sample of n=25 what is the probability that X is
a. less than 95
t(95) = (95-100)/[10/sqrt(25)] = -5/2 = -2.5
P(x < 95) = P(t < -2.5 when df = 24) = 0.0098
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c. above 102.2?
t(102.2) = (102.2-100)/[10/sqrt(25)] = 2.2/2 = 1.1
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P(x > 102.2) = P(t > 1.1 when df = 24) = 0.1411
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Cheers,
Stan H.
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Answer by kkasko(46) (Show Source): You can put this solution on YOUR website!
Solution is incorrect I forgot to add something. Referr to stanbon
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SOLUTION: Given a normal distribution &#956; = 100 with and &#963;=10, if you select a sample of n=25 what is the probability that X is a. less than 95 c. above 102.2?

SOLUTION: Given a normal distribution μ = 100 with and σ=10, if you select a sample of n=25 what is the probability that X is a. less than 95 c. above 102.2?