[-2011, 2012] There are 2012 positive numbers, and 2011 negative numbers, and 1 zero. So there are 2012+2011+1 or 4024 numbers to choose from. We have to choose a pair of positive numbers or a pair of negative numbers. If we choose the numbers with replacement: P[(positive 1st AND positive 2nd) OR (negative 1st AND negative 2nd)] = P(positive 1st)×P(positive 2nd) + P(negative 1st)×P(negative 2nd) If the choosing of the numbers is done with replacement× + × which works out to be = .4997515528 If the choosing of the numbers is done without replacement × + × which works out to be .4996272675 Edwin