# SOLUTION: The average hourly wage of employees in a large nationwide industry is \$12.96. Assume the variable is normally distributed, with a standard deviation of \$4.46. In a randomly select

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: The average hourly wage of employees in a large nationwide industry is \$12.96. Assume the variable is normally distributed, with a standard deviation of \$4.46. In a randomly select      Log On

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 Question 545072: The average hourly wage of employees in a large nationwide industry is \$12.96. Assume the variable is normally distributed, with a standard deviation of \$4.46. In a randomly selected sample of 10,000 such employees, how many of them (correct to the nearest hundred) would you expect to be earning between \$9.00 and \$17.00 per hour?Answer by stanbon(57377)   (Show Source): You can put this solution on YOUR website!The average hourly wage of employees in a large nationwide industry is \$12.96. Assume the variable is normally distributed, with a standard deviation of \$4.46. In a randomly selected sample of 10,000 such employees, how many of them (correct to the nearest hundred) would you expect to be earning between \$9.00 and \$17.00 per hour? ----- z(9) = (9-12.96)/4.46 = -0.8879 ---- z(17) = (17-12.96)/4.46 = 0.9058 --------------------------------------- P(9 < x < 17) = P(-0.8879 < z < 0.9058) = 0.6302 ================ Cheers, Stan H. ================