SOLUTION: If you are not prepaired for a test and you have 3 true or false questions what is the probablity of getting 2 out of the 3 correct?

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Question 544597: If you are not prepaired for a test and you have 3 true or false questions what is the probablity of getting 2 out of the 3 correct?

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
If you are not prepaired for a test and you have 3 true or false questions what is the probablity of getting 2 out of the 3 correct?
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Binomial Problem with n = 3 and p(correct) = 1/2
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P(x = 2 or 3) = P(2) + P(3)
= 3C2(1/2)^3 + 3C3(1/2)^2
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= (3+1)(1/2)^3
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= 4/8
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= 1/2
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Cheers,
Stan H.
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