SOLUTION: The times for completing one circuit of a bicycle course are normally distributed with a mean of 80.3 minutes and a standard deviation of 7.8 minutes. An association wants to spons

Question 542613: The times for completing one circuit of a bicycle course are normally distributed with a mean of 80.3 minutes and a standard deviation of 7.8 minutes. An association wants to sponsor a race and provide prizes for the top 15% of riders. Where should they expect to set the cutoff time to earn a prize?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The times for completing one circuit of a bicycle course are normally distributed with a mean of 80.3 minutes and a standard deviation of 7.8 minutes. An association wants to sponsor a race and provide prizes for the top 15% of riders. Where should they expect to set the cutoff time to earn a prize?
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Find z-value with a left tail of 0.85
invNorm(0.85) = 1.0364
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Find the correspondiing raw score value using x = zs+u
x = 1.0364*7.8+80.3
x = 88.38 munutes
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Cheers,
Stan H.
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