SOLUTION: The mean is 112 oz, and the standard deviation is 40 oz. Compute the probability that the mean from a sample of 49 will fall between 103 and 121 oz
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Question 542099: The mean is 112 oz, and the standard deviation is 40 oz. Compute the probability that the mean from a sample of 49 will fall between 103 and 121 oz
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The mean is 112 oz, and the standard deviation is 40 oz. Compute the probability that the mean from a sample of 49 will fall between 103 and 121 oz
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z(103) = (103-112)/[40/sqrt(49)] = -1.575
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z(121) = (121-112)/[40/sqrt(49)] = +1.575
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P(103 < x-bar < 121) = P(-1.575 < z < +1.575) = 0.8847
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Cheers,
Stan H.
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