SOLUTION: Alright, I'm trying to help my friend understand probability, and she gave me this problem. I got completely lost, and any help would be most appreciated! Here's the Question: Y

Question 538798: Alright, I'm trying to help my friend understand probability, and she gave me this problem. I got completely lost, and any help would be most appreciated! Here's the Question:
You draw thee cards from a standard 52-card deck. Without replacing the cards, what is the probability that you draw an ace a king, and a queen IN ORDER?

Again, any help would be most appreciated. I tried finding the probability by finding first the probability of drawing an ace, a king, and a queen in any order. It's the last part that stumped me.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You draw thee cards from a standard 52-card deck. Without replacing the cards, what is the probability that you draw an ace a king, and a queen IN ORDER?
----
# of ways to get ace,king,queen: 4*4*4 = 64
---
3 of ways to get 3 cards: 52*51*50 = 132600
---
P(ace,king,queen) = 64/132600 = 0.000483
================
Cheers,
Stan H.
RELATED QUESTIONS
If i ate 1/3 of corn muffins, gave 1/4 to a friend and I have 9 left, how many did I... (answered by ankor@dixie-net.com)

Hi. I'm very confused In how to get the answer to this problem: t-3+2(t+2) I tried to... (answered by ankor@dixie-net.com)

How do I solve this problem? I'm trying to help my daughter and I'm lost. 2a to the... (answered by KMST,mananth)

Hi. This is the problem I have: The length of a rectangle is 3 times its width. If its (answered by josgarithmetic)

Please help me with this question; I am trying to help my granddaughter and I am so lost. (answered by rfer)

I'm very lost for this question. I tried it by myself and with my friend in math class... (answered by solver91311)

I am gaving a really hard time grasping this concept in my math clas. We are working on... (answered by stanbon)

Hello, I am trying to help my daughter with a math question that she doesn't... (answered by solver91311)

This is frustrating. I've been working on this problem for too long now. It's a simple... (answered by kev82)