SOLUTION: How do I set this up(not on the calculation):
Hospital records show that of patients suffering from a certain disease, 75% die of it. What is the probability that of 6 randomly se
Algebra.Com
Question 535841: How do I set this up(not on the calculation):
Hospital records show that of patients suffering from a certain disease, 75% die of it. What is the probability that of 6 randomly selected patients, 4 will recover?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The probability of 
successes in 
trials where 
is the probability of success on any given trial is given by:
\ =\ \left(n\cr k\right\)\left(p\right)^k\left(1\,-\,p\right)^{n\,-\,k})
Where )
is the number of combinations of things taken at a time and is calculated by !})
If 75% die, 25% recover. So calculate:
\ =\ \left(6\cr 4\right\)\left(0.25\right)^4\left(1\,-\,0.25\right)^{6\,-\,4}\ =\ 15\left(0.25\right)^4\left(0.75\right)^2)
I did part of your arithmetic for you. You can do the rest for yourself.
John
My calculator said it, I believe it, that settles it
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