SOLUTION: Kobe Bryant makes 80% of his free throws in his god season. What is the probability that he will make at least 6 of his next 8 free-throw attempts? Use the probability table given

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Question 533397: Kobe Bryant makes 80% of his free throws in his god season. What is the probability that he will make at least 6 of his next 8 free-throw attempts? Use the probability table given to solve the problem.
Answer by stanbon(57962) (Show Source):
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Kobe Bryant makes 80% of his free throws in his good season. What is the probability that he will make at least 6 of his next 8 free-throw attempts? Use the probability table given to solve the problem.
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Binomial with n = 8 and p(make free throw) = 0.8
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P(6<= x <=8) = 1 - binomcdf(8,0.8,5) = 0.7969
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Cheers,
Stan H.
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