SOLUTION: Which equation is used in this problem,, Sample of 50 packages is selected , the mean amount is different from 8.17 ozs, then mean amount is 8.159 ounces and the standard deviation
Algebra.Com
Question 531761: Which equation is used in this problem,, Sample of 50 packages is selected , the mean amount is different from 8.17 ozs, then mean amount is 8.159 ounces and the standard deviation is 0.051 ozs. Is there evidence that the population meAN amount is different from 8.17 ozs by using .05 level of significance and determine the p-value and interpret its meaning.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Which equation is used in this problem,,
-------------------
Sample of 50 packages is selected , the mean amount is different from 8.17 ozs, then mean amount is 8.159 ounces and the standard deviation is 0.051 ozs.
Is there evidence that the population meAN amount is different from 8.17 ozs by using .05 level of significance and determine the p-value and interpret its meaning.
----
Ho: u = 0.817
Ha: u is not equal to 0.817 (claim)
-----
x-bar = 8.159
t(8.159) = (8.159-8.17)/[0.051/sqrt(50)] = -1.5251
-----
p-value = 2*P(t < -1.5251 when df = 49) = 0.1337
----
Since the p-value is greater than 5%, fail to reject Ho.
The test results do not support the claim.
=======================
Cheers,
Stan H.
==============
RELATED QUESTIONS
A chocolate company uses machines to package candies, the packages are labeled as 8... (answered by stanbon)
In a jelly bean store, the owner asked the clerk to package the jelly beans so that any... (answered by edjones)
The number of fluid ounces in a large bottle of tide is 18 ozs more then the amount in a... (answered by checkley77)
39 packages are randomly selected from packages received by a parcel service. The sample... (answered by Boreal)
Use the confidence level and sample data to find a confidence interval for estimating the (answered by rothauserc)
1) A bank asks customers to evaluate the drive-thru service as good, average, or poor.... (answered by Boreal)
In this problem, how do they get the 2.682?
Forty-nine items are randomly selected... (answered by rothauserc,addingup)
7. The serum cholesterol levels in milligrams/deciliter (mg/dL) in a certain... (answered by Fombitz)
A population has a standard deviation of 50. A random sample of 100 items from this... (answered by stanbon)