SOLUTION: A committee contains 9 women and 6 men. If we choose three random people for a subcommittee, how many ways could we choose exactly 1 woman?
Here's my work:  # ways to pick 1 wom
Algebra.Com
Question 530188:  A committee contains 9 women and 6 men. If we choose three random people for a subcommittee, how many ways could we choose exactly 1 woman?
Here's my work:  # ways to pick 1 woman: 9C1 = 9
                 # ways to pick 2 men: 6C2 = 15
                   Answer: 135 ways to choose exactly 1 woman
Is this answer correct?  If not, could you explain the steps and answer?
Really appreciate an answer to this. Need to submit homework online tonight! 
Found 2 solutions by  stanbon, jim_thompson5910:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
 That looks good to me.
Cheers,
Stan H.
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Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
 You are correct, congrats. This is of course assuming that order does not matter. 
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