I'm not sure what you mean by "n(factor)k" I would answer "permutations", for the number of 4-letter "words" is P(26,4) or on the TI-84, it's 26 nPr 4 And it is calculated by 26×25×24×23 = 358800 Maybe that's what you mean by n(factor)k. I am not familiar with "n(factor)k", but maybe you call that "26(factor)4". I'm only familiar with calling it "The number of permutations of 26 things taken 4 at a time". Regardless of what people call it, the number of 4-letter "words" without repeating letters is: 26×25×24×23 = 358800 Edwin