# SOLUTION: 3. A sample of consumers was surveyed regarding their visits to a computer chain store and if the store was conveniently located. The following table summarizes the results of tha

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: 3. A sample of consumers was surveyed regarding their visits to a computer chain store and if the store was conveniently located. The following table summarizes the results of tha      Log On

 Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Algebra: Probability and statistics Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Probability-and-statistics Question 522945: 3. A sample of consumers was surveyed regarding their visits to a computer chain store and if the store was conveniently located. The following table summarizes the results of that survey: Visits Convenient Not Convenient Totals Often 60 20 80 Occasional 25 35 60 Never 5 50 55 Column Totals 90 105 195 a. What is this table called b. Are frequency of visits and convenience independent or related? Explain your answer. What is the probability of a survey respondent being convenient to a store? c. What is the probability of a survey respondent being not convenient to a store and never visiting a store in the chain? Answer by stanbon(57327)   (Show Source): You can put this solution on YOUR website!A sample of consumers was surveyed regarding their visits to a computer chain store and if the store was conveniently located. The following table summarizes the results of that survey: Visits Convenient Not Convenient Totals Often 60 20 80 Occasional 25 35 60 Never 5 50 55 Column Totals 90 105 195 a. What is this table called: A contingency table. ------------------------------- b. Are frequency of visits and convenience independent or related? Explain your answer. P(often) = 80/195 ; P(convenient) = 90/195 P(often)*P(confenient) = 0.1893 P(often | convenient) = 60/90 = 2/3 Since P(oft | conven) is not equal to P(oft)*P(conven) they are dependent factors. -------------------------------------------------------------- What is the probability of a survey respondent being convenient to a store? P(convenient+ = 90/195 ----------------------------- c. What is the probability of a survey respondent being not convenient to a store and never visiting a store in the chain? P(not convenient AND never visiting) = P(con | never)*P(never) = 5/55 * 55/195 = 5/195 =========================== Cheers, Stan H. ================================