SOLUTION: The length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hour
Algebra.Com
Question 508913: The length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hours. Find the 90 percent confidence interval on the standard deviation of the length of stay.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The length of stay (in hours) for a sample of 12 pneumonia patients at Santa Theresa Memorial Hospital was found to have a mean of 126 hours and a standard deviation of 21.663 hours. Find the 90 percent confidence interval on the standard deviation of the length of stay.
---
sample mean = 126
margin of error = 1.645*21.663/sqrt(12) = 10.29
---
90%CI: 126-10.29 < u < 126+10.29
============
Cheers,
Stan H.
============
RELATED QUESTIONS
A journal article reported that the mean hospital stay following a particular surgical... (answered by CPhill)
A hospital would like to determine the average length of stay for its ... (answered by ewatrrr)
Hospital administrators wish to determine the average length of stay for all surgical... (answered by stanbon)
In a random sample of 14 people, the mean length of stay at a hospital was 7.1 days.... (answered by Boreal)
Hospital capacity. When Memorial Hospital is filled to capacity, it has 18 more people in (answered by Theo)
6. Suppose the national average for medication error is one out of every 1000 patients. A (answered by stanbon)
This is a capacity question.
when Memorial Hospital is filled to capacity, it has 18... (answered by scott8148)
The average length of stay in a chronic disease hospital for a certain type of patient is (answered by stanbon)
The length of stay for patients in some 20 hospitals was 3.8 days with a standard... (answered by stanbon)