SOLUTION: From a group of 12 people I am to form 4 teams of 3 players each. In how many ways can this be done. (This is closely related to the previous problem, but note that the teams are n

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Question 495631: From a group of 12 people I am to form 4 teams of 3 players each. In how many ways can this be done. (This is closely related to the previous problem, but note that the teams are not ordered.
I tried doing (12x11x10x9)/(3x2x1)
and
12!/4!3!
but both are wrong

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
From a group of 12 people I am to form 4 teams of 3 players each. In how many ways can this be done.
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# of ways to form the 1st team of 3: 12C3 = (12*11*10)/(1*2*3) = 220 ways
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# of ways to form the 2nd team: 9C3 = (9*8*7)/(1*2*3) = 84 ways
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# of ways to form the 3rd team: 6C3 = (6*5*4)/(1*2*3) = 20 ways
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# of ways to form the 4th team: 3C3 = 1 way
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Total # of ways: 220*84*20*1 = 369,600
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Cheers,
Stan H.

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