SOLUTION: I am taking statistics online and having trouble with this problem. I asked my teacher for help but he still hasnt gotten back to me on my question. Any help would be great thank y

Question 494558: I am taking statistics online and having trouble with this problem. I asked my teacher for help but he still hasnt gotten back to me on my question. Any help would be great thank you
Answer the following:
(A) Find the binomial probability P(x = 5), where n = 13 and p = 0.70.
(B) Set up, without solving, the binomial probability P(x is at most 5) using probability notation.
(C) How would you find the normal approximation to the binomial probability P(x = 5) in part A? Please show how you would calculate � and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You are the 3rd or 4th person in the past week
to post this problem. This is the answer I
gave to the others.
==================
Cheers,
Stan H.
==================

(A) Find the binomial probability P(x = 5), where n = 14 and p = 0.70.
Ans: 14C5(0.7)^5(0.3)^9 = binompdf(14,0.7,5) = 0.00660.7746
------------------------------
(B) Set up, without solving, the binomial probability P(x is at most 5) using probability notation.
P(0<= x <=5) = 14C0(0.7)^0*(0.3)^14+14C1(0.7)*(0.3)^13+ etc.
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(C) How would you find the normal approximation to the binomial probability P(x = 5) in part A?
Please show how you would calculate � and σ in the formula for the normal approximation to the binomial, and show the final formula you would use without going through all the calculations
u = np = 14*0.7 = 2
s = sqrt(npq) = sqrt(2*0.3) = 0.7746
---------------
binomial probability (x = 5)
equals normal approximation probability (4.5 < x < 5.5)
============
Cheers,
Stan H.
===========

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