SOLUTION: A federal
report stated that 88% of children under age 18 were
covered by health insurance in 2000. How large a
sample is needed to estimate the true proportion of
covered chil
Algebra.Com
Question 491599: A federal
report stated that 88% of children under age 18 were
covered by health insurance in 2000. How large a
sample is needed to estimate the true proportion of
covered children with 90% confidence with a
confidence interval 0.05 wide?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A federal
report stated that 88% of children under age 18 were
covered by health insurance in 2000. How large a
sample is needed to estimate the true proportion of
covered children with 90% confidence with a
confidence interval 0.05 wide?
--------
If the CI is 0.05 wide
2E = 0.05
E = 0.025
---
Since E = z*sqrt(pq/n)
sqrt(n) = [z/E]*sqrt(pq)
---
So, n = [z/E]^2*pq
----
n = [1.645/0.025]^2*0.18*0.72
---
n = 562 when rounded up
============================
Cheers,
Stan H.
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