SOLUTION: Statistics have never been one of my strong suits and for some reason I am just drawing a blank on these. I am an adult learner right now and am having a hard time working on thing

Question 486566: Statistics have never been one of my strong suits and for some reason I am just drawing a blank on these. I am an adult learner right now and am having a hard time working on things from 20 years ago. Can you please show me how you work this out too so I can learn from it???
1. The Florida Tourist Commission estimates that a person visiting Florida will visit Disney World, Busch Gardens, or both with probabilities 0.5, 0.3, and 0.2, respectively. Find the probability that a person visiting Florida will visit Busch Gardens, given that the person did visit Disney World .
2. A word contains 20 marbles--5 red, 9 blue, 3 green, and 3 yellow
If the 20 marbles used to spell the word are placed in a glass jar
and two marbles are chosen at random in succession and without replacement, what is the probability (as a
reduced fraction) of choosing a marble other than red each time?
Thank you!

Answer by chessace(471) (Show Source): You can put this solution on YOUR website!
1. P(B given A) = P(A and B)/P(A)
P(BG given DW) = 0.2 / 0.5 = 0.4
2. 5 are red, 15 not so much.
First is not red: 15/20 = 3/4
And (implies Times) second is not red = 14/19
Answer = (3/4) * (14/19) = (3*7)/(2*19) = 21/38.

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