Probability that all will be nondefective is



P(1st is nondefective)×P(2nd is nondefective)×P(3rd is nondefective)



(a) with replacement.  The probabilities do not change:



P(1st is nondefective)×P(2nd is nondefective)×P(3rd is nondefective) =





 

-----



(b) without replacement.  The probabilities do change:



P(1st is nondefective)×P(2nd is nondefective)×P(3rd is nondefective) =



 



So there is very little difference between the probabilies.



Edwin>/pre>

 

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