SOLUTION: A student wishes to scehdule each of 6 elective courses in different terms. If none of these has prerequisites, in how many different orders may the courses be taken?

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Again, 6 courses.

So how many can be the first one? Answer is any of the six --> 6.
and how many could then be second? Answer is any of the remaining five (since one of the courses was chosen to be first) --> 5.
and third? Answer is 4.

etc

So altogether we have 6*5*4*3*2*1 which is 6!. You work it out.

Jon