Hi,
Let x,y,z represent the number of chairs, tables and chests
Question states***
2x+4y+8z = 2000
x+3y+6z = 1400
2x+3y+4z = 1300
Solving simultaneously in the manner of Your choice:
x = 200, the number of chairs
y = 100, the number of tables
z = 150, the number of chests