Question 482872: Dice is a popular game in gambling casinos. Two dice are tossed, and various amounts are paid according to the outcome. In a certain game, if a nine or six occurs on the first roll, the player wins. What is the probability of winning on the first roll?
Here is another problem that I have no idea how I would have to solve it/.Can I get one of the tutors to assist me with it please? Thank you!
Answer by bucky(2189) (Show Source):
You can put this solution on YOUR website!
Again, another dice problem. As I indicated in the answer to one of your other problems, there are 36 possible outcomes on the roll of a pair of fair dice. These outcomes are:
Out of the 36 possible outcomes, how many of the dice rolls total 6 or 9. Count them up. You should find there are 9 of these "winners" beginning with 1,5 and ending with 6,3. So the probability of winning on the first roll by rolling a 6 or a 9 is the number of winners (9 of them) divided by the total number of possible outcomes (36). 9 divided by 36 reduces to 1 divided by 4 which has a decimal equivalent of 0.25 (or 25%). You have a one in four chance of winning on the first roll. This suggests that in the long run on every 4 rolls you are likely to be a winner for one of those rolls.
Good luck. Just keep working at it and eventually it will start to make sense.