# SOLUTION: Dice is a popular game in gambling casinos. Two dice are tossed, and various amounts are paid according to the outcome. In a certain game, if a nine or six occurs on the first roll

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Dice is a popular game in gambling casinos. Two dice are tossed, and various amounts are paid according to the outcome. In a certain game, if a nine or six occurs on the first roll      Log On

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 Click here to see ALL problems on Probability-and-statistics Question 482872: Dice is a popular game in gambling casinos. Two dice are tossed, and various amounts are paid according to the outcome. In a certain game, if a nine or six occurs on the first roll, the player wins. What is the probability of winning on the first roll? Here is another problem that I have no idea how I would have to solve it/.Can I get one of the tutors to assist me with it please? Thank you!Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!Again, another dice problem. As I indicated in the answer to one of your other problems, there are 36 possible outcomes on the roll of a pair of fair dice. These outcomes are: . 1,1 1,2 1,3 1,4 1,5 1,6 2,1 2,2 2,3 2,4 2,5 2,6 3,1 3,2 3,3 3,4 3,5 3,6 4,1 4,2 4,3 4,4 4,5 4,6 5,1 5,2 5,3 5,4 5,5 5,6 6,1 6,2 6,3 6,4 6,5 6,6 . Out of the 36 possible outcomes, how many of the dice rolls total 6 or 9. Count them up. You should find there are 9 of these "winners" beginning with 1,5 and ending with 6,3. So the probability of winning on the first roll by rolling a 6 or a 9 is the number of winners (9 of them) divided by the total number of possible outcomes (36). 9 divided by 36 reduces to 1 divided by 4 which has a decimal equivalent of 0.25 (or 25%). You have a one in four chance of winning on the first roll. This suggests that in the long run on every 4 rolls you are likely to be a winner for one of those rolls. . Good luck. Just keep working at it and eventually it will start to make sense. .