SOLUTION: Dice is a popular game in gambling casinos. Two dice are tossed, and various amounts are paid according to the outcome. In a certain game, if a nine or six occurs on the first roll
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Question 482872: Dice is a popular game in gambling casinos. Two dice are tossed, and various amounts are paid according to the outcome. In a certain game, if a nine or six occurs on the first roll, the player wins. What is the probability of winning on the first roll?
Here is another problem that I have no idea how I would have to solve it/.Can I get one of the tutors to assist me with it please? Thank you!
Answer by bucky(2189) (Show Source): You can put this solution on YOUR website!
Again, another dice problem. As I indicated in the answer to one of your other problems, there are 36 possible outcomes on the roll of a pair of fair dice. These outcomes are:
.
1,1
1,2
1,3
1,4
1,5
1,6
2,1
2,2
2,3
2,4
2,5
2,6
3,1
3,2
3,3
3,4
3,5
3,6
4,1
4,2
4,3
4,4
4,5
4,6
5,1
5,2
5,3
5,4
5,5
5,6
6,1
6,2
6,3
6,4
6,5
6,6
.
Out of the 36 possible outcomes, how many of the dice rolls total 6 or 9. Count them up. You should find there are 9 of these "winners" beginning with 1,5 and ending with 6,3. So the probability of winning on the first roll by rolling a 6 or a 9 is the number of winners (9 of them) divided by the total number of possible outcomes (36). 9 divided by 36 reduces to 1 divided by 4 which has a decimal equivalent of 0.25 (or 25%). You have a one in four chance of winning on the first roll. This suggests that in the long run on every 4 rolls you are likely to be a winner for one of those rolls.
.
Good luck. Just keep working at it and eventually it will start to make sense.
.
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