SOLUTION: A box contains 4 red and 5 green balls. Three balls are drawn. The probability 2 red and 1 green are drawn are drawn is.
1, 1/3
2, 4/9
c. 5/14
d. 3/5 My answer is 4/9, 4/9=
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Question 48179This question is from textbook Finite math
: A box contains 4 red and 5 green balls. Three balls are drawn. The probability 2 red and 1 green are drawn are drawn is.
1, 1/3
2, 4/9
c. 5/14
d. 3/5 My answer is 4/9, 4/9=.44 amd 5/9=.55 is this right. Thanks for any help given.
This question is from textbook Finite math
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A box contains 4 red and 5 green balls. Three balls are drawn. The probability 2 red and 1 green are drawn are drawn is.
Draw the 2 red in 4C2 = 6 ways
Draw the 1 green in 5C1=5 ways
Draw 3 of any kind 9C3 = 9*8*7/1*2*3 = 84
Prob (2R and 1G)= #of ways to suceed / # of possible outcomes
= 6*5/84 = 15/42=5/14
Cheers,
Stan H.
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