# SOLUTION: I need help with this, is the estimate .03 and the sample size is 1? I am lost. Can you show me how to do this. Thank you. A consumer agency wants to estimate, at a 99% confiden

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: I need help with this, is the estimate .03 and the sample size is 1? I am lost. Can you show me how to do this. Thank you. A consumer agency wants to estimate, at a 99% confiden      Log On

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 Click here to see ALL problems on Probability-and-statistics Question 480117: I need help with this, is the estimate .03 and the sample size is 1? I am lost. Can you show me how to do this. Thank you. A consumer agency wants to estimate, at a 99% confidence level, the proportion of all households that own at least one pet. What is the sample size that would limit the maximum error of the estimate to within .03 of the population proportion?Answer by stanbon(57387)   (Show Source): You can put this solution on YOUR website!A consumer agency wants to estimate, at a 99% confidence level, the proportion of all households that own at least one pet. What is the sample size that would limit the maximum error of the estimate to within .03 of the population proportion? ------ n = [z/E]^2*pq ---- Find the z-value with a 0.005 left tail: z = 2.57 --- E = 0.03 --- You are not given a value for "p" so you should use p = 1/2, which is the "least biased" estimate of p. --- n = [2.5758/0.03]^2*(1/4) ---- n = 7372.11*(1/4) n = 1843.02 --- Round up to n = 1844 ========================= Cheers, Stan H.