# SOLUTION: Smallville Bank has 650 checking accounts. A recent sample of 50 of these customers showed 26 have a Visa card with the bank. Construct a 99% or .99 confidence interval for the p

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Smallville Bank has 650 checking accounts. A recent sample of 50 of these customers showed 26 have a Visa card with the bank. Construct a 99% or .99 confidence interval for the p      Log On

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 Question 478988: Smallville Bank has 650 checking accounts. A recent sample of 50 of these customers showed 26 have a Visa card with the bank. Construct a 99% or .99 confidence interval for the proportion of checking account customers who have a Visa account with the bank. Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!Smallville Bank has 650 checking accounts. A recent sample of 50 of these customers showed 26 have a Visa card with the bank. Construct a 99% or .99 confidence interval for the proportion of checking account customers who have a Visa account with the bank. ----------------------- sample proportion: 26/50 = 0.13 ---- ME = 2.5758*sqrt[0.13*0.87/650] = 0.034 ---- 99% CI: 0.13-0.034 < p < 0.13+0.034 --- 0.096 < p < 0.164 =================== Cheers, Stan H. =============