Hi,

For a normal distribution, find the value of z such that 36% of the total area is to the right of z

|Using Excel function NORMSINV(0.36)= -.3585

 P(z = -.3585) represents the total area to the 'left' of z being 36% 

 P(z = .3585) represents the total area to the 'right' of z being 36% 

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