SOLUTION: Hi you all I really need help with this question.....Scores on the Standford-Binet I ntelligence scale have a mean of 100 and a standard deviation of 16, and are presuemd to be nor

Question 477047: Hi you all I really need help with this question.....Scores on the Standford-Binet I ntelligence scale have a mean of 100 and a standard deviation of 16, and are presuemd to be normally distributed. A person who scores 84 on this scale has what percentile rank within the population? Show all work as to how this is obtained. I dont even no where to begin or how can someone please help me and direct me with this question please!!!!!!!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Scores on the Standford-Binet Intelligence scale have a mean of 100 and a standard deviation of 16, and are presumed to be normally distributed. A person who scores 84 on this scale has what percentile rank within the population?
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z(84) = (84-100)/16 = -1
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P(x < 84) = P(z < -1) = 0.1587
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So 15.87% of the population has a score less than 84.
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The person has percentile score of 15.87%ile or 16%ile if you found up.
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Cheers,
Stan H.
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