SOLUTION: if a 3-digit number (000 to 999) i chosen at random, find the probability that exactly 1 digit will be >5.

Algebra.Com
Question 475325: if a 3-digit number (000 to 999) i chosen at random, find the
probability that exactly 1 digit will be >5.

Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
3 ways of choosing a place,
4 ways of selecting a digit > 5 in the chosen place,
6 ways of filling any one of the 2 remaining places,
6 ways of filling the last place, assuming repetition of digits.
==> 3*4*6*6 = 432
==> probability is .

RELATED QUESTIONS

Hi, I'm trying to solve this problem: If a 3-digit number (000 to 999) is chosen at... (answered by venugopalramana,biplavmehta)
an integer from 100 through 999 inclusive, is to be chosen at random. What is the... (answered by stanbon)
If three numbers from 100 to 999 are chosen at random, one at a time, find the... (answered by ikleyn)
If three numbers from 100 to 999 are chosen at random, one at a time, find the... (answered by Edwin McCravy)
An integer from 100 through 999, inclusive, is to be chosen at random. What is the... (answered by drk)
an integer from 100 through 999 inclusive, is to be chosen at random. What is the... (answered by jim_thompson5910)
form a four-digit numbers using the set of digits {0, 1, 2, 3, 4, 5, 6}. If one... (answered by Edwin McCravy)
Choose one number at random from 1, 2, 3, 4, ... , 999, 1000. What is the probability... (answered by edjones)
Lottery Ticket. In a bin are an equal number of balls marked with the digits 1-9. Three... (answered by stanbon)