SOLUTION: John and Bill each roll a die, and the two dice are compared to see if both numbers match. If they do this twice, what is the probability that both times they fail to get a match.

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: John and Bill each roll a die, and the two dice are compared to see if both numbers match. If they do this twice, what is the probability that both times they fail to get a match.       Log On

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Question 474152: John and Bill each roll a die, and the two dice are compared to see if both numbers match. If they do this twice, what is the probability that both times they fail to get a match.
A. 1/3
B.11/36
C. 1/36
D. 25/36
E. 1/6
Please show me how to set it up and explain why its done this way.

Answer by edjones(7569) About Me  (Show Source):
You can put this solution on YOUR website!
5/6 of the time they wont match.
(5/6)^2=25/36 the probability that both times they fail to get a match.
.
Ed