SOLUTION: Please help me. A word consist of 5 consonants and 4 vowels. Three letters are selected at random. What is the probability of having more than one vowel?

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nCr=combination of n things taken r at a time.=n!/((n-r)!*r!)
Assuming that the letters are chosen without replacement:
((4C2 * 5C1) + (4C3))/9C3
=((6*5)+4)/9C3
=34/84
=17/42 the probability of having more than one vowel.
.
Ed