SOLUTION: Plz help with process!
Two students are selected at random from a class of 14 males and 6 females. Find the probability that both students are males (to two decimals).
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Question 471927: Plz help with process!
Two students are selected at random from a class of 14 males and 6 females. Find the probability that both students are males (to two decimals).
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
This is a binomial process. There are only two possible outcomes on any given trial: You either pick a guy or a girl. There are 14 guys out of 20 people (0.7 probability) and there are 6 girls out of 20 people (0.3) probability. The probabilities are PER TRIAL.
You want to know the probability of exactly two males out of two attempts.
The probability of 
successes in 
trials where 
is the probability of success on any given trial is given by:
\ =\ \left(n\cr k\right\)\left(p\right)^k\left(1\,-\,p\right)^{n\,-\,k})
Where )
is the number of combinations of things taken at a time and is calculated by !})
For your problem:
Hint:
\ =\ \left(n\cr 0\right\)\ =\ 1\ \forall\ n\ >\ 0\ \in\ \mathbb{Z})
And
John
My calculator said it, I believe it, that settles it
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