SOLUTION: in a random sample of four microwave ovens, the mean repair cost was $60.00 and the standard deviation was $11.00. Assume the variable is normally distributed use a t distribution

Question 471536: in a random sample of four microwave ovens, the mean repair cost was $60.00 and the standard deviation was $11.00. Assume the variable is normally distributed use a t distribution to construct a 99% confidence interval for the population of the mean u. what is the margin for u?
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

Sample of 4, mean of 60 and sd = 11

99% confidence interval  P = .995,  Degree of Freedom = 3, t = 5.841 (Stat Trek)

ME = 5.841* [11/sqrt(4)] = 32.1255

 60-32.1255 < μ < 60 + 32.1255

  

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