SOLUTION: The average number of mosquitoes in a stagnant pond is 80 per square meter with a standard deviation of 8. If 16 square meters are chosen at random for a mosquito count, find the

Question 471525: The average number of mosquitoes in a stagnant pond is 80 per square meter with a standard deviation of 8. If 16 square meters are chosen at random for a mosquito count, find the probability that the average of those counts is more than 81.6 mosquitoes per square meter. Assume that the variable is normally distributed.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

 

Hi,

z = (x-u)/s = (81.6-80)/8 = .2 

 P(x >81.6) = P( z > .2) = 1 - P(z ≤ .2) = 1 - .57926 = .42074 

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