SOLUTION: Jane is cooking beans and rice for dinner tonight. She has 3 cans of black beans, 1 can of red beans, and 4 cans of garbanzo beans in her cupboard. If she grabs a can of beans with

Question 471011: Jane is cooking beans and rice for dinner tonight. She has 3 cans of black beans, 1 can of red beans, and 4 cans of garbanzo beans in her cupboard. If she grabs a can of beans without looking at the label, what is the probability of her making black beans and rice for dinner?
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Basically the question is about the beans (and not the rice)

P(Black Beans) = (# of cans of black beans)/(# of cans total)

P(Black Beans) = 3/8

So the probability is 3/8, which in decimal form is 0.375
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