SOLUTION: A bag contains 44 U.S. quarters and six Canadian quarters. (The coins are identical in size.) If four quarters are randomly picked from the bag, what is the probability of getting

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Question 470691: A bag contains 44 U.S. quarters and six Canadian quarters. (The coins are identical in size.) If four quarters are randomly picked from the bag, what is the probability of getting at least one Canadian quarter?
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

Note: The probability of x successes in n trials is: 

P = nCx* p%5Ex%2Aq%5E%28n-x%29 where p and q are the probabilities of success and failure respectively. 

In this case p = 6/50 = .12 & q .88

nCx = n%21%2F%28x%21%28n-x%29%21%29

4 coins picked: n = 4

 P(at least one Canadian) = 1-P(no Canadian)

                          = 1 -.88^4

                          = .4003