Hi,

Event A, 3 on the 1st roll  P(A) = 6/36 = 1/6

Event B, sum is 7    P(B) = 6/36 = 1/6

Event C, double      P(C) =  6/36 = 1/6

If events are independent, then the probability of them both occurring is the

 product of the probabilities of each occurring. 

P(A and B)= P(A)*P(B) = 1/6*1/6 = 1/36 = P(both occur) a 3 rolled and then a 4

  Events A and B are Independent  

___1_2_3__4__5__6  (First roll)

1|_2_3_4__5__6__7

2|_3_4_5__6__7__8

3|_4_5_6__7__8__9

4|_5_6___8__9_10

5|_6_7_8__9_10_11

6|_7_8_9_10_11_12

 

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