SOLUTION: I would highly appreciate assistance from a tutor on how to do these three difficult homework problems that are due tonight. I don't know if I am solving them correctly. Please sho

Question 468063: I would highly appreciate assistance from a tutor on how to do these three difficult homework problems that are due tonight. I don't know if I am solving them correctly. Please show me if I am mislead.
4. (1 point) Suppose in a village 50% of the people farm, 60% of the people fish, and 70% of the people either farm or fish. What is the percentage of people in the village who both farm and fish?
.5+.6= 1.1 - .7 = .4?
5. (1 point) Suppose in a village 50% of the people farm, 60% of the people fish, and 70% of the people either farm or fish. If a randomly chosen person farms, what is the probability that this person also fishes?
.5 x .6= .3?
6. (1 point) Suppose 48% of a village�s population is male. 30% of the men smoke, 20% of the women smoke. If a randomly chosen person is found to be a smoker, what is the probability that this person is a man? Round answer to two places after the decimal point.
.48 x .3 = .144= .14?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
This is very easy once you understand Venn diagrams.
Let x=the intersection of farm and fish: .5-x+.6-x+x=.7 the union of farm and fish.
4)1.1-x=.7
x=.4 answer
farm DISABLED_event_only= .1
fish DISABLED_event_only= .2
.
5).4/.5=.8
.
6)
.48*.3=.144 male smokers
.52*.2=.104 female smokers
--------------add
======>.248
.
.144/.248 = .58 probability the this person is a man.
.
Ed
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