SOLUTION: the manager of a nearby cafe found that the cost to produce 100 cups of coffee is $11.02, while the cost to produce 400 cups is $40.12 . Each cup of coffee is sold for 75 cents per

Question 466896: the manager of a nearby cafe found that the cost to produce 100 cups of coffee is $11.02, while the cost to produce 400 cups is $40.12 . Each cup of coffee is sold for 75 cents per cup. Asume the cost c(x) is a linear function od x, the number of cups produced.
How many cups of coffee will the cafe have to sell in order to break even? c(x)= r(x).

How many cups of coffee will need to sold in order to make a profit of 4500? round to the nearst cup?
Answer by Big Poop(157) (Show Source): You can put this solution on YOUR website!
sdgfERROR Algebra::Solver::Engine::invoke_solver_noengine: solver not defined for name 'linear_egfsdqguation'.

Error occurred executing solver 'linear_egfsdqguation' .

Solved by pluggable solver: DESCRIBE a linear EQUATION: slope, intercepts, etc

this equation defines a vertical line.

X intercept: 2. X intercept is the intersection of the line with the x axis.

Y intercept: not defined (the line IS vertical)

Slope: not defined, can be thought of as infinite

Solved by pluggable solver: SOLVE quadratic equation with variable

Quadratic equation (in our case ) has the following solutons:

For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=16 is greater than zero. That means that there are two solutions: .

Quadratic expression can be factored:

Again, the answer is: 3, -1. Here's your graph:

sds
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