# SOLUTION: Please show me how to do these hard homework problems: 1. if Pr(E)= 0.59 then Pr(E')=? 2. If Pr(E)= 0.6, Pr(EUF)= 0.8, Pr(E&#8745;F)= 0.25, then Pr(F)=? 1.05= 0.6 + F F= .9

Algebra ->  Algebra  -> Probability-and-statistics -> SOLUTION: Please show me how to do these hard homework problems: 1. if Pr(E)= 0.59 then Pr(E')=? 2. If Pr(E)= 0.6, Pr(EUF)= 0.8, Pr(E&#8745;F)= 0.25, then Pr(F)=? 1.05= 0.6 + F F= .9      Log On

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 Click here to see ALL problems on Probability-and-statistics Question 465765: Please show me how to do these hard homework problems: 1. if Pr(E)= 0.59 then Pr(E')=? 2. If Pr(E)= 0.6, Pr(EUF)= 0.8, Pr(E∩F)= 0.25, then Pr(F)=? 1.05= 0.6 + F F= .99 3. S= {a,b,c,d,e}, Pr{a,b,c}= 0.55, Pr{c}= 0.15, Pr{c,d}= 0.35, Then Pr{e}=? 0.55 + 0.35 - 0.15 = e= .75 Please show me if I did these correctlyAnswer by kingme18(98)   (Show Source): You can put this solution on YOUR website!1. E and E' are complementary events. So, if E happens, then E' doesn't, and if E' happens, then E doesn't. Thus, if Pr(E) = 0.59, then Pr(E') = 1 - 0.59 = 0.41 2. You were almost right. The only problem you had is that 1.05 - 0.6 = 0.45, not 0.99. You did 1.05 - 0.06...double check your decimal placement :) 3. You found Pr{a,b,c,d}. Pr{e} is the leftover: 1 - 0.75 = 0.25.