SOLUTION: A psychologist wants to interview subjects with IQ scores in the top 1%. IQ scores are normally distributed with mean of 100 and a standard deviation of 15. Find the score that sep
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Question 465433: A psychologist wants to interview subjects with IQ scores in the top 1%. IQ scores are normally distributed with mean of 100 and a standard deviation of 15. Find the score that separating the top 1% of IQ from the bottom 99%.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A psychologist wants to interview subjects with IQ scores in the top 1%. IQ scores are normally distributed with mean of 100 and a standard deviation of 15. Find the score that separating the top 1% of IQ from the bottom 99%.
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Find the z-value with a left-tail of 0.99.
invNorm(0.99) = 2.3263
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score = 2.3263*15 + 100 = 135 when rounded up
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Cheers,
Stan H.
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