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put this solution on YOUR website!The number of defects in a sample of 20 parts is recorded for quality control purposes; over the last year the number of defects and their occurrence rate has been:
0 defects, 82%;
1 defect, 13%,
2 defects, 4%,
3 defects, 1%.
Find the expected number of defects in the next sample of 20 parts.
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E(x) = 0*0.82 + 1*0.13 + 2*0.04 + 3*0.01
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E(x) = 0 + 0.13 + 0.08 + 0.03 = 0.24 is the expected # of
defects in a sample of 20 parts.
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Cheers,
Stan H.