SOLUTION: it was found that 25% of all applicants for a position scored less than 160 points on an aptitude test. the standard deviation of the scores was 25. if the distribution score was n

Question 464796: it was found that 25% of all applicants for a position scored less than 160 points on an aptitude test. the standard deviation of the scores was 25. if the distribution score was normally distributed, what was the mean score
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
it was found that 25% of all applicants for a position scored less than 160 points on an aptitude test. the standard deviation of the scores was 25. if the distribution score was normally distributed, what was the mean score
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Find the z-score with a left tail of 0.25.
invNorm(0.25) = -0.6745
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Using x = zs+u, solve for "u":
160 = -0.6745*25 + u
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u = 160 + 16.8622
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u = 176.8622
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Cheers,
Stan H.

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